[VulnHub] Hemisphere Lynx Walkthrough

A walkthrough for the Hemisphere Lynx virtual machine, available from VulnHub.

[VulnHub] Hemisphere Lynx Walkthrough

Difficulty level: Easy
Aim: capture two flags (user and root)
Author: d4t4s3c

Download: https://www.vulnhub.com/entry/hemisphere-lynx,577/

Information Gathering

The IP address of the target can be obtained via arp-scan:

sudo arp-scan --interface=eth1



We can then scan the target with nmap to determine open ports and services:

nmap -sC -sV -vv

The output from nmap shows the following open ports and services:

  • port 21/tcp - FTP - vsftpd 3.0.3
  • port 22/tcp - SSH - OpenSSH 7.9p1
  • port 80/tcp - HTTP - Apache httpd server 2.4.38
  • port 139/tcp - SMB - Samba
  • port 445/tcp - SMB - Samba


Let's take a look at the HTTP service running on port 80:

I initially ran a scan with gobuster to brute-force hidden files and directories, but this did not return anything of use:

gobuster dir -u -w /usr/share/wordlists/dirbuster/directory-list-2.3-medium.txt

From here, I decided to create a custom wordlist based on the content of the above webpage:

cewl -w wordlist.txt

At this stage, the only other option to explore was the SMB service.

enum4linux can be used to enumerate SMB on Linux and Windows systems to discover shares on a device, password policies, user listings etc:


This reveals a user called 'johannes' which can be used with our custom wordlist to potentially brute-force the FTP and/or SSH login.

Gaining Access

I decided to try brute-forcing the SSH service first, using the above information:

hydra -l johannes -P wordlist.txt ssh

Success! We have a password for johannes.

(N.B. this username and password combination also works for the FTP service)

We can now login to the SSH service:

ssh [email protected]

The user.txt flag can be found in the home directory of johannes:

cat user.txt

Privilege Escalation

Within the /Desktop directory of the current user there is a file named .creds which contains a Base64 encoded string:

This can be decoded by running:

echo "MjBLbDdpUzFLQ2FuaU84RFdNemg6dG9vcg==" | base64 -d

The output from this reveals the root credentials in reverse.

To reverse this string into the correct format we can run:

echo "20Kl7iS1KCaniO8DWMzh:toor" | rev

From here we can su to the root user and obtain the root.txt flag from the /root directory:

su root
cd /root
ls -l
cat root.txt

Please feel free to contact me via Twitter and thanks for reading.